3.2.84 \(\int \frac {\cos ^8(c+d x)}{(a+a \sin (c+d x))^{5/2}} \, dx\) [184]

Optimal. Leaf size=63 \[ -\frac {8 a^2 \cos ^9(c+d x)}{99 d (a+a \sin (c+d x))^{9/2}}-\frac {2 a \cos ^9(c+d x)}{11 d (a+a \sin (c+d x))^{7/2}} \]

[Out]

-8/99*a^2*cos(d*x+c)^9/d/(a+a*sin(d*x+c))^(9/2)-2/11*a*cos(d*x+c)^9/d/(a+a*sin(d*x+c))^(7/2)

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Rubi [A]
time = 0.08, antiderivative size = 63, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.087, Rules used = {2753, 2752} \begin {gather*} -\frac {8 a^2 \cos ^9(c+d x)}{99 d (a \sin (c+d x)+a)^{9/2}}-\frac {2 a \cos ^9(c+d x)}{11 d (a \sin (c+d x)+a)^{7/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[Cos[c + d*x]^8/(a + a*Sin[c + d*x])^(5/2),x]

[Out]

(-8*a^2*Cos[c + d*x]^9)/(99*d*(a + a*Sin[c + d*x])^(9/2)) - (2*a*Cos[c + d*x]^9)/(11*d*(a + a*Sin[c + d*x])^(7
/2))

Rule 2752

Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_), x_Symbol] :> Simp[b*(g*C
os[e + f*x])^(p + 1)*((a + b*Sin[e + f*x])^(m - 1)/(f*g*(m - 1))), x] /; FreeQ[{a, b, e, f, g, m, p}, x] && Eq
Q[a^2 - b^2, 0] && EqQ[2*m + p - 1, 0] && NeQ[m, 1]

Rule 2753

Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_), x_Symbol] :> Simp[(-b)*(
g*Cos[e + f*x])^(p + 1)*((a + b*Sin[e + f*x])^(m - 1)/(f*g*(m + p))), x] + Dist[a*((2*m + p - 1)/(m + p)), Int
[(g*Cos[e + f*x])^p*(a + b*Sin[e + f*x])^(m - 1), x], x] /; FreeQ[{a, b, e, f, g, m, p}, x] && EqQ[a^2 - b^2,
0] && IGtQ[Simplify[(2*m + p - 1)/2], 0] && NeQ[m + p, 0]

Rubi steps

\begin {align*} \int \frac {\cos ^8(c+d x)}{(a+a \sin (c+d x))^{5/2}} \, dx &=-\frac {2 a \cos ^9(c+d x)}{11 d (a+a \sin (c+d x))^{7/2}}+\frac {1}{11} (4 a) \int \frac {\cos ^8(c+d x)}{(a+a \sin (c+d x))^{7/2}} \, dx\\ &=-\frac {8 a^2 \cos ^9(c+d x)}{99 d (a+a \sin (c+d x))^{9/2}}-\frac {2 a \cos ^9(c+d x)}{11 d (a+a \sin (c+d x))^{7/2}}\\ \end {align*}

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Mathematica [A]
time = 0.21, size = 49, normalized size = 0.78 \begin {gather*} -\frac {2 \cos ^9(c+d x) (13+9 \sin (c+d x))}{99 d (1+\sin (c+d x))^2 (a (1+\sin (c+d x)))^{5/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[Cos[c + d*x]^8/(a + a*Sin[c + d*x])^(5/2),x]

[Out]

(-2*Cos[c + d*x]^9*(13 + 9*Sin[c + d*x]))/(99*d*(1 + Sin[c + d*x])^2*(a*(1 + Sin[c + d*x]))^(5/2))

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Maple [A]
time = 0.55, size = 57, normalized size = 0.90

method	result	size
default	\(\frac {2 \left (1+\sin \left (d x +c \right )\right ) \left (\sin \left (d x +c \right )-1\right )^{5} \left (9 \sin \left (d x +c \right )+13\right )}{99 a^{2} \cos \left (d x +c \right ) \sqrt {a +a \sin \left (d x +c \right )}\, d}\)	\(57\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cos(d*x+c)^8/(a+a*sin(d*x+c))^(5/2),x,method=_RETURNVERBOSE)

[Out]

2/99/a^2*(1+sin(d*x+c))*(sin(d*x+c)-1)^5*(9*sin(d*x+c)+13)/cos(d*x+c)/(a+a*sin(d*x+c))^(1/2)/d

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^8/(a+a*sin(d*x+c))^(5/2),x, algorithm="maxima")

[Out]

integrate(cos(d*x + c)^8/(a*sin(d*x + c) + a)^(5/2), x)

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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 161 vs. \(2 (55) = 110\).
time = 0.36, size = 161, normalized size = 2.56 \begin {gather*} -\frac {2 \, {\left (9 \, \cos \left (d x + c\right )^{6} - 23 \, \cos \left (d x + c\right )^{5} - 52 \, \cos \left (d x + c\right )^{4} + 4 \, \cos \left (d x + c\right )^{3} - 8 \, \cos \left (d x + c\right )^{2} + {\left (9 \, \cos \left (d x + c\right )^{5} + 32 \, \cos \left (d x + c\right )^{4} - 20 \, \cos \left (d x + c\right )^{3} - 24 \, \cos \left (d x + c\right )^{2} - 32 \, \cos \left (d x + c\right ) - 64\right )} \sin \left (d x + c\right ) + 32 \, \cos \left (d x + c\right ) + 64\right )} \sqrt {a \sin \left (d x + c\right ) + a}}{99 \, {\left (a^{3} d \cos \left (d x + c\right ) + a^{3} d \sin \left (d x + c\right ) + a^{3} d\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^8/(a+a*sin(d*x+c))^(5/2),x, algorithm="fricas")

[Out]

-2/99*(9*cos(d*x + c)^6 - 23*cos(d*x + c)^5 - 52*cos(d*x + c)^4 + 4*cos(d*x + c)^3 - 8*cos(d*x + c)^2 + (9*cos
(d*x + c)^5 + 32*cos(d*x + c)^4 - 20*cos(d*x + c)^3 - 24*cos(d*x + c)^2 - 32*cos(d*x + c) - 64)*sin(d*x + c) +
32*cos(d*x + c) + 64)*sqrt(a*sin(d*x + c) + a)/(a^3*d*cos(d*x + c) + a^3*d*sin(d*x + c) + a^3*d)

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Sympy [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: SystemError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)**8/(a+a*sin(d*x+c))**(5/2),x)

[Out]

Exception raised: SystemError >> excessive stack use: stack is 3278 deep

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Giac [A]
time = 4.45, size = 68, normalized size = 1.08 \begin {gather*} -\frac {64 \, {\left (9 \, \sqrt {2} \sqrt {a} \sin \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} - 11 \, \sqrt {2} \sqrt {a} \sin \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9}\right )}}{99 \, a^{3} d \mathrm {sgn}\left (\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^8/(a+a*sin(d*x+c))^(5/2),x, algorithm="giac")

[Out]

-64/99*(9*sqrt(2)*sqrt(a)*sin(-1/4*pi + 1/2*d*x + 1/2*c)^11 - 11*sqrt(2)*sqrt(a)*sin(-1/4*pi + 1/2*d*x + 1/2*c
)^9)/(a^3*d*sgn(cos(-1/4*pi + 1/2*d*x + 1/2*c)))

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int \frac {{\cos \left (c+d\,x\right )}^8}{{\left (a+a\,\sin \left (c+d\,x\right )\right )}^{5/2}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cos(c + d*x)^8/(a + a*sin(c + d*x))^(5/2),x)

[Out]

int(cos(c + d*x)^8/(a + a*sin(c + d*x))^(5/2), x)

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